and i am using psu with 32 Amp maximum output but only 5.2 Amp is running in the solution...
In my experience, I've found that the cell will take what current it can use from the power supply, and no more. You can't force-feed more current than the cell circuit is able to use.
For example, you have a 100 Amp power supply and a cell which is sized to demand 20 Amperes. The cell will take the 20 Amps and no more. It's a self limiting circuit, and 80 Amps are still available. If you wish to use more of the power supply's capacity, you need to increase the electrode size, all the connections and the cables (everything in the entire circuit), to effectively accomplish your goal.
Neglecting any part of the planned circuit upgrade will limit the amount of current the entire circuit can use. Using leads that are too small, for example, will be a choke point, limiting the amount of current that can flow, even if everything else has larger capacity. It's the same if the method of connecting power cables to the electrode leads aren't large enough capacity to carry the full current of the rest of the circuit.
When you upgrade the volume of the cell, be sure to upgrade the entire electrical system to match it, and all will be well.
Edit: It's good electrical practice to design a circuit to demand no more than 80% of the power supply's capacity. Your power supply will usually run comfortably at 80%, where nearer to 100% it will struggle and possibly burn out, due to the strain.
Also remember, the first run of a cell uses a lot of energy creating the precursors to make chlorate ions. Recharging the used electrolyte, with its mixture of precursor ions combined with the newly added chloride ions, allows it to produce more chlorate quicker, due to the head start the precursor ions give it. So yes, the second (and more) runs of the electrolyte will produce more chlorate than the first run.
Edited by WSM, 13 January 2020 - 05:54 AM.